ya well my boss is a cunt then lol, k well he gave me the one problem, 4 subs at 4 ohms each, 2 subs to a side, one 2 channel amp that has to be at 2 ohms. heres what i figured
ah ha discovered it, its That(SPACE)verbal so: That Verbal. lol found it and pm'd him thx for what help you guys were able to give. argh, wut a bs task....
no it was a different problem
i have 2 problems one was 4 subs at 4 ohms each 2 ohms at the amp, thats wut the diagram was for, but i wasnt sure if it was correct but i still havent figured out the 3 subs at 3 ohms per sub, total circuit resistance of 1.5 ohms
ok here is the answer
4 subs at 4 ohms a piece can be wired
A. At 2 ohms stereo. Two subs per channell. All positives and negatives connected together
B. 1 ohm mono. All positives and negatives ran together with the amp being bridged.
C. Heres the tricky one. 4 ohm mono. Through series parallell wiring. Take two subs. Wire the negative terminal of one sub to the positive terminal of the second sub. This will leave you an open positive and an open negative terminal.
Wire the other two subs in that fashion. This will give you two sets of subs wired to 8 ohms. Bridge your amp to those two sets of speakers and the impedance will be a total of 4 ohms.
As for the 3-3ohm woofers you can not achieve a 1.5 ohm load. These woofers will only achive an overall 1 ohm or 9 ohm load.